4014022131313 has 4 divisors (see below), whose sum is σ = 4107371483248. Its totient is φ = 3920672779380.

The previous prime is 4014022131289. The next prime is 4014022131377. The reversal of 4014022131313 is 3131312204104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4014022131313 - 2¹³ = 4014022123121 is a prime.

It is a super-2 number, since 2×4014022131313² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4014022111313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46674675903 + ... + 46674675988.

It is an arithmetic number, because the mean of its divisors is an integer number (1026842870812).

Almost surely, 2^{4014022131313} is an apocalyptic number.

4014022131313 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

4014022131313 is a deficient number, since it is larger than the sum of its proper divisors (93349351935).

4014022131313 is an equidigital number, since it uses as much as digits as its factorization.

4014022131313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93349351934.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4014022131313 its reverse (3131312204104), we get a palindrome (7145334335417).

The spelling of 4014022131313 in words is "four trillion, fourteen billion, twenty-two million, one hundred thirty-one thousand, three hundred thirteen".