Base | Representation |
---|---|
bin | 100101011100001011… |
… | …111101010000110011 |
3 | 10211202200220212121120 |
4 | 211130023331100303 |
5 | 1124313021002201 |
6 | 30245050153323 |
7 | 2622140533461 |
oct | 453413752063 |
9 | 124680825546 |
10 | 40201344051 |
11 | 1605a679890 |
12 | 795b422843 |
13 | 3a389ba55b |
14 | 1d3521d831 |
15 | 10a4509536 |
hex | 95c2fd433 |
40201344051 has 16 divisors (see below), whose sum is σ = 58498754688. Its totient is φ = 24354420800.
The previous prime is 40201344041. The next prime is 40201344083. The reversal of 40201344051 is 15044310204.
It is a cyclic number.
It is not a de Polignac number, because 40201344051 - 213 = 40201335859 is a prime.
It is a super-3 number, since 3×402013440513 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (40201344041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 168981 + ... + 330086.
It is an arithmetic number, because the mean of its divisors is an integer number (3656172168).
Almost surely, 240201344051 is an apocalyptic number.
40201344051 is a deficient number, since it is larger than the sum of its proper divisors (18297410637).
40201344051 is a wasteful number, since it uses less digits than its factorization.
40201344051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 501522.
The product of its (nonzero) digits is 1920, while the sum is 24.
Adding to 40201344051 its reverse (15044310204), we get a palindrome (55245654255).
The spelling of 40201344051 in words is "forty billion, two hundred one million, three hundred forty-four thousand, fifty-one".
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