Base | Representation |
---|---|
bin | 111010100000000011001… |
… | …001000100111001110011 |
3 | 112020022200121121101211221 |
4 | 322200003021010321303 |
5 | 1011331222334200313 |
6 | 12314454445045511 |
7 | 563305604015014 |
oct | 72400311047163 |
9 | 15208617541757 |
10 | 4020142100083 |
11 | 130aa2945757a |
12 | 54b169556897 |
13 | 232136a67555 |
14 | dc80c45500b |
15 | 6e88e444c8d |
hex | 3a803244e73 |
4020142100083 has 2 divisors, whose sum is σ = 4020142100084. Its totient is φ = 4020142100082.
The previous prime is 4020142100017. The next prime is 4020142100189. The reversal of 4020142100083 is 3800012410204.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4020142100083 is a prime.
It is not a weakly prime, because it can be changed into another prime (4020142100483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010071050041 + 2010071050042.
It is an arithmetic number, because the mean of its divisors is an integer number (2010071050042).
Almost surely, 24020142100083 is an apocalyptic number.
4020142100083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4020142100083 is an equidigital number, since it uses as much as digits as its factorization.
4020142100083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4020142100083 its reverse (3800012410204), we get a palindrome (7820154510287).
The spelling of 4020142100083 in words is "four trillion, twenty billion, one hundred forty-two million, one hundred thousand, eighty-three".
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