Base | Representation |
---|---|
bin | 111010100001001001100… |
… | …110100011001001001011 |
3 | 112020102201222222212221111 |
4 | 322201021212203021023 |
5 | 1011341133000344433 |
6 | 12315212034151151 |
7 | 563350106661364 |
oct | 72411146431113 |
9 | 15212658885844 |
10 | 4021324231243 |
11 | 1310485769180 |
12 | 54b4394224b7 |
13 | 232294943647 |
14 | dc8c1452b6b |
15 | 6e90d100dcd |
hex | 3a8499a324b |
4021324231243 has 16 divisors (see below), whose sum is σ = 4396495656960. Its totient is φ = 3647753752000.
The previous prime is 4021324231219. The next prime is 4021324231261. The reversal of 4021324231243 is 3421324231204.
It is a cyclic number.
It is not a de Polignac number, because 4021324231243 - 221 = 4021322134091 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4021324231343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62653218 + ... + 62717368.
It is an arithmetic number, because the mean of its divisors is an integer number (274780978560).
Almost surely, 24021324231243 is an apocalyptic number.
4021324231243 is a deficient number, since it is larger than the sum of its proper divisors (375171425717).
4021324231243 is a wasteful number, since it uses less digits than its factorization.
4021324231243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76538.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 4021324231243 its reverse (3421324231204), we get a palindrome (7442648462447).
The spelling of 4021324231243 in words is "four trillion, twenty-one billion, three hundred twenty-four million, two hundred thirty-one thousand, two hundred forty-three".
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