Base | Representation |
---|---|
bin | 111010100001001110001… |
… | …100100010110110110011 |
3 | 112020102221101000101221211 |
4 | 322201032030202312303 |
5 | 1011341312213103103 |
6 | 12315223430100551 |
7 | 563352034026664 |
oct | 72411614426663 |
9 | 15212841011854 |
10 | 4021401300403 |
11 | 13105152183a3 |
12 | 54b45b1aa757 |
13 | 2322a78b89b6 |
14 | dc8cb79536b |
15 | 6e914c7636d |
hex | 3a84e322db3 |
4021401300403 has 2 divisors, whose sum is σ = 4021401300404. Its totient is φ = 4021401300402.
The previous prime is 4021401300379. The next prime is 4021401300409. The reversal of 4021401300403 is 3040031041204.
4021401300403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021401300403 - 29 = 4021401299891 is a prime.
It is not a weakly prime, because it can be changed into another prime (4021401300409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010700650201 + 2010700650202.
It is an arithmetic number, because the mean of its divisors is an integer number (2010700650202).
Almost surely, 24021401300403 is an apocalyptic number.
4021401300403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021401300403 is an equidigital number, since it uses as much as digits as its factorization.
4021401300403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 4021401300403 its reverse (3040031041204), we get a palindrome (7061432341607).
The spelling of 4021401300403 in words is "four trillion, twenty-one billion, four hundred one million, three hundred thousand, four hundred three".
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