Base | Representation |
---|---|
bin | 111010100001001110110… |
… | …101010111010101100010 |
3 | 112020102222010011001120202 |
4 | 322201032311113111202 |
5 | 1011341322433013442 |
6 | 12315224451305202 |
7 | 563352224005265 |
oct | 72411665272542 |
9 | 15212863131522 |
10 | 4021412001122 |
11 | 1310520266a6a |
12 | 54b4628ab202 |
13 | 2322a9b94499 |
14 | dc8ccd7ccdc |
15 | 6e915b8bc32 |
hex | 3a84ed57562 |
4021412001122 has 4 divisors (see below), whose sum is σ = 6032118001686. Its totient is φ = 2010706000560.
The previous prime is 4021412001077. The next prime is 4021412001169. The reversal of 4021412001122 is 2211002141204.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4016452883881 + 4959117241 = 2004109^2 + 70421^2 .
It is a super-3 number, since 3×40214120011223 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4021412001094 and 4021412001103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005353000279 + ... + 1005353000282.
Almost surely, 24021412001122 is an apocalyptic number.
4021412001122 is a deficient number, since it is larger than the sum of its proper divisors (2010706000564).
4021412001122 is a wasteful number, since it uses less digits than its factorization.
4021412001122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2010706000563.
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 4021412001122 its reverse (2211002141204), we get a palindrome (6232414142326).
The spelling of 4021412001122 in words is "four trillion, twenty-one billion, four hundred twelve million, one thousand, one hundred twenty-two".
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