Base | Representation |
---|---|
bin | 111010100001010000000… |
… | …101101101000111011011 |
3 | 112020110000120210001110202 |
4 | 322201100011231013123 |
5 | 1011341343330434401 |
6 | 12315230522532415 |
7 | 563352601012652 |
oct | 72412005550733 |
9 | 15213016701422 |
10 | 4021433061851 |
11 | 1310531141227 |
12 | 54b46996710b |
13 | 2322b135965a |
14 | dc8d1aa2199 |
15 | 6e91794c06b |
hex | 3a85016d1db |
4021433061851 has 2 divisors, whose sum is σ = 4021433061852. Its totient is φ = 4021433061850.
The previous prime is 4021433061827. The next prime is 4021433061869. The reversal of 4021433061851 is 1581603341204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4021433061851 is a prime.
It is not a weakly prime, because it can be changed into another prime (4021433061251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010716530925 + 2010716530926.
It is an arithmetic number, because the mean of its divisors is an integer number (2010716530926).
Almost surely, 24021433061851 is an apocalyptic number.
4021433061851 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021433061851 is an equidigital number, since it uses as much as digits as its factorization.
4021433061851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 38.
The spelling of 4021433061851 in words is "four trillion, twenty-one billion, four hundred thirty-three million, sixty-one thousand, eight hundred fifty-one".
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