Base | Representation |
---|---|
bin | 111010100001111000100… |
… | …111111011001011110011 |
3 | 112020111202222102122021001 |
4 | 322201320213323023303 |
5 | 1011344241424333021 |
6 | 12315422214542431 |
7 | 563405466302506 |
oct | 72417047731363 |
9 | 15214688378231 |
10 | 4022113121011 |
11 | 1310850000797 |
12 | 54b619667a17 |
13 | 23238c20651b |
14 | dc95812913d |
15 | 6e9574d1091 |
hex | 3a8789fb2f3 |
4022113121011 has 2 divisors, whose sum is σ = 4022113121012. Its totient is φ = 4022113121010.
The previous prime is 4022113120951. The next prime is 4022113121017. The reversal of 4022113121011 is 1101213112204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4022113121011 - 221 = 4022111023859 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4022113121011.
It is not a weakly prime, because it can be changed into another prime (4022113121017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011056560505 + 2011056560506.
It is an arithmetic number, because the mean of its divisors is an integer number (2011056560506).
Almost surely, 24022113121011 is an apocalyptic number.
4022113121011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022113121011 is an equidigital number, since it uses as much as digits as its factorization.
4022113121011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 4022113121011 its reverse (1101213112204), we get a palindrome (5123326233215).
The spelling of 4022113121011 in words is "four trillion, twenty-two billion, one hundred thirteen million, one hundred twenty-one thousand, eleven".
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