Base | Representation |
---|---|
bin | 111010100001111111101… |
… | …101110101111110111011 |
3 | 112020112002021100001200211 |
4 | 322201333231311332323 |
5 | 1011400012410104313 |
6 | 12315442105211551 |
7 | 563411442565252 |
oct | 72417755657673 |
9 | 15215067301624 |
10 | 4022232113083 |
11 | 1310901194248 |
12 | 54b651490bb7 |
13 | 2323aaa69732 |
14 | dc969c61799 |
15 | 6e962b87e3d |
hex | 3a87fb75fbb |
4022232113083 has 2 divisors, whose sum is σ = 4022232113084. Its totient is φ = 4022232113082.
The previous prime is 4022232113063. The next prime is 4022232113087. The reversal of 4022232113083 is 3803112322204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4022232113083 is a prime.
It is a super-2 number, since 2×40222321130832 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4022232113087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011116056541 + 2011116056542.
It is an arithmetic number, because the mean of its divisors is an integer number (2011116056542).
Almost surely, 24022232113083 is an apocalyptic number.
4022232113083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022232113083 is an equidigital number, since it uses as much as digits as its factorization.
4022232113083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 4022232113083 its reverse (3803112322204), we get a palindrome (7825344435287).
The spelling of 4022232113083 in words is "four trillion, twenty-two billion, two hundred thirty-two million, one hundred thirteen thousand, eighty-three".
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