Search a number
-
+
4023121433 = 411912571999
BaseRepresentation
bin1110111111001011…
…1111011000011001
3101101101012202002112
43233302333120121
531214404341213
61503113242105
7201460653002
oct35762773031
911341182075
104023121433
111784a46751
12943403335
134c1658836
142a24521a9
151882e0ea8
hexefcbf619

4023121433 has 16 divisors (see below), whose sum is σ = 4161024000. Its totient is φ = 3887308800.

The previous prime is 4023121423. The next prime is 4023121457. The reversal of 4023121433 is 3341213204.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4023121433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4023121399 and 4023121408.

It is not an unprimeable number, because it can be changed into a prime (4023121423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2011568 + ... + 2013566.

It is an arithmetic number, because the mean of its divisors is an integer number (260064000).

Almost surely, 24023121433 is an apocalyptic number.

It is an amenable number.

4023121433 is a deficient number, since it is larger than the sum of its proper divisors (137902567).

4023121433 is a wasteful number, since it uses less digits than its factorization.

4023121433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2488.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 4023121433 is about 63428.0807923431. The cubic root of 4023121433 is about 1590.4537598425.

Adding to 4023121433 its reverse (3341213204), we get a palindrome (7364334637).

The spelling of 4023121433 in words is "four billion, twenty-three million, one hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 41 191 257 1999 7831 10537 49087 81959 381809 513743 2012567 15654169 21063463 98124913 4023121433