Base | Representation |
---|---|
bin | 10010010010111000100000… |
… | …10111010101001100011011 |
3 | 12021110001211211000022200101 |
4 | 21021130100113111030123 |
5 | 20233122031200310321 |
6 | 221321550130320231 |
7 | 11321416314655255 |
oct | 1111342027251433 |
9 | 167401754008611 |
10 | 40231233213211 |
11 | 11900a74360677 |
12 | 46190ba729077 |
13 | 195aa34601891 |
14 | 9d12b86dccd5 |
15 | 49b7901b6791 |
hex | 2497105d531b |
40231233213211 has 2 divisors, whose sum is σ = 40231233213212. Its totient is φ = 40231233213210.
The previous prime is 40231233213167. The next prime is 40231233213229. The reversal of 40231233213211 is 11231233213204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40231233213211 - 239 = 39681477399323 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40231233213211.
It is not a weakly prime, because it can be changed into another prime (40231233213511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20115616606605 + 20115616606606.
It is an arithmetic number, because the mean of its divisors is an integer number (20115616606606).
Almost surely, 240231233213211 is an apocalyptic number.
40231233213211 is a deficient number, since it is larger than the sum of its proper divisors (1).
40231233213211 is an equidigital number, since it uses as much as digits as its factorization.
40231233213211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 40231233213211 its reverse (11231233213204), we get a palindrome (51462466426415).
The spelling of 40231233213211 in words is "forty trillion, two hundred thirty-one billion, two hundred thirty-three million, two hundred thirteen thousand, two hundred eleven".
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