Base | Representation |
---|---|
bin | 10010010010111001111101… |
… | …10011000101100110110011 |
3 | 12021110010212002220001100201 |
4 | 21021130332303011212303 |
5 | 20233130130113210311 |
6 | 221322155315500031 |
7 | 11321444524414261 |
oct | 1111347663054663 |
9 | 167403762801321 |
10 | 40232012241331 |
11 | 11901334077a69 |
12 | 46192975b7617 |
13 | 195ab29b20b71 |
14 | 9d134dd69431 |
15 | 49b7d87999c1 |
hex | 24973ecc59b3 |
40232012241331 has 2 divisors, whose sum is σ = 40232012241332. Its totient is φ = 40232012241330.
The previous prime is 40232012241319. The next prime is 40232012241371. The reversal of 40232012241331 is 13314221023204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40232012241331 - 27 = 40232012241203 is a prime.
It is a super-2 number, since 2×402320122413312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40232012241331.
It is not a weakly prime, because it can be changed into another prime (40232012241371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20116006120665 + 20116006120666.
It is an arithmetic number, because the mean of its divisors is an integer number (20116006120666).
Almost surely, 240232012241331 is an apocalyptic number.
40232012241331 is a deficient number, since it is larger than the sum of its proper divisors (1).
40232012241331 is an equidigital number, since it uses as much as digits as its factorization.
40232012241331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 40232012241331 its reverse (13314221023204), we get a palindrome (53546233264535).
The spelling of 40232012241331 in words is "forty trillion, two hundred thirty-two billion, twelve million, two hundred forty-one thousand, three hundred thirty-one".
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