Base | Representation |
---|---|
bin | 10010010011001010111100… |
… | …10000100100111100001011 |
3 | 12021111000101112120012002101 |
4 | 21021211132100210330023 |
5 | 20233302313240001024 |
6 | 221330304145014231 |
7 | 11322216500163415 |
oct | 1111453620447413 |
9 | 167430345505071 |
10 | 40241130000139 |
11 | 1190519288a122 |
12 | 461b001024377 |
13 | 195b950ac1c13 |
14 | 9d1976c759b5 |
15 | 49bb6de87c44 |
hex | 24995e424f0b |
40241130000139 has 2 divisors, whose sum is σ = 40241130000140. Its totient is φ = 40241130000138.
The previous prime is 40241130000011. The next prime is 40241130000161. The reversal of 40241130000139 is 93100003114204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40241130000139 - 27 = 40241130000011 is a prime.
It is not a weakly prime, because it can be changed into another prime (40241130000199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20120565000069 + 20120565000070.
It is an arithmetic number, because the mean of its divisors is an integer number (20120565000070).
Almost surely, 240241130000139 is an apocalyptic number.
40241130000139 is a deficient number, since it is larger than the sum of its proper divisors (1).
40241130000139 is an equidigital number, since it uses as much as digits as its factorization.
40241130000139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 40241130000139 in words is "forty trillion, two hundred forty-one billion, one hundred thirty million, one hundred thirty-nine", and thus it is an aban number.
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