Base | Representation |
---|---|
bin | 111010100011110111100… |
… | …101001010100110000011 |
3 | 112020201021102100222210202 |
4 | 322203313211022212003 |
5 | 1011413122213313011 |
6 | 12320413423515415 |
7 | 563512331665025 |
oct | 72436745124603 |
9 | 15221242328722 |
10 | 4024243104131 |
11 | 1311743358618 |
12 | 54bb12a58b6b |
13 | 23263b591773 |
14 | dcabad7c015 |
15 | 6ea2e4bc23b |
hex | 3a8f794a983 |
4024243104131 has 2 divisors, whose sum is σ = 4024243104132. Its totient is φ = 4024243104130.
The previous prime is 4024243104121. The next prime is 4024243104227. The reversal of 4024243104131 is 1314013424204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4024243104131 - 230 = 4023169362307 is a prime.
It is a super-2 number, since 2×40242431041312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4024243104094 and 4024243104103.
It is not a weakly prime, because it can be changed into another prime (4024243104121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012121552065 + 2012121552066.
It is an arithmetic number, because the mean of its divisors is an integer number (2012121552066).
Almost surely, 24024243104131 is an apocalyptic number.
4024243104131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024243104131 is an equidigital number, since it uses as much as digits as its factorization.
4024243104131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4024243104131 its reverse (1314013424204), we get a palindrome (5338256528335).
The spelling of 4024243104131 in words is "four trillion, twenty-four billion, two hundred forty-three million, one hundred four thousand, one hundred thirty-one".
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