Base | Representation |
---|---|
bin | 111010100011110111100… |
… | …101101010010100000011 |
3 | 112020201021102121121000121 |
4 | 322203313211222110003 |
5 | 1011413122231442201 |
6 | 12320413430401111 |
7 | 563512333045555 |
oct | 72436745522403 |
9 | 15221242547017 |
10 | 4024243234051 |
11 | 1311743437197 |
12 | 54bb12b00197 |
13 | 23263b608941 |
14 | dcabadb34d5 |
15 | 6ea2e4e59a1 |
hex | 3a8f796a503 |
4024243234051 has 2 divisors, whose sum is σ = 4024243234052. Its totient is φ = 4024243234050.
The previous prime is 4024243233931. The next prime is 4024243234061. The reversal of 4024243234051 is 1504323424204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4024243234051 - 213 = 4024243225859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4024243233998 and 4024243234016.
It is not a weakly prime, because it can be changed into another prime (4024243234061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012121617025 + 2012121617026.
It is an arithmetic number, because the mean of its divisors is an integer number (2012121617026).
Almost surely, 24024243234051 is an apocalyptic number.
4024243234051 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024243234051 is an equidigital number, since it uses as much as digits as its factorization.
4024243234051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92160, while the sum is 34.
Adding to 4024243234051 its reverse (1504323424204), we get a palindrome (5528566658255).
The spelling of 4024243234051 in words is "four trillion, twenty-four billion, two hundred forty-three million, two hundred thirty-four thousand, fifty-one".
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