Base | Representation |
---|---|
bin | 1011101101100101110… |
… | …00000100010000100001 |
3 | 1102110202020200121012202 |
4 | 11312302320010100201 |
5 | 23043140322003411 |
6 | 504513011502545 |
7 | 41034444030611 |
oct | 5666270042041 |
9 | 1373666617182 |
10 | 402433000481 |
11 | 145741a346a6 |
12 | 65bb1bb7a55 |
13 | 2bc4570c8b5 |
14 | 15699372a41 |
15 | a7052dc83b |
hex | 5db2e04421 |
402433000481 has 2 divisors, whose sum is σ = 402433000482. Its totient is φ = 402433000480.
The previous prime is 402433000393. The next prime is 402433000511. The reversal of 402433000481 is 184000334204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 386206317025 + 16226683456 = 621455^2 + 127384^2 .
It is a cyclic number.
It is not a de Polignac number, because 402433000481 - 214 = 402432984097 is a prime.
It is a super-2 number, since 2×4024330004812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (402433009481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201216500240 + 201216500241.
It is an arithmetic number, because the mean of its divisors is an integer number (201216500241).
Almost surely, 2402433000481 is an apocalyptic number.
It is an amenable number.
402433000481 is a deficient number, since it is larger than the sum of its proper divisors (1).
402433000481 is an equidigital number, since it uses as much as digits as its factorization.
402433000481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 402433000481 its reverse (184000334204), we get a palindrome (586433334685).
The spelling of 402433000481 in words is "four hundred two billion, four hundred thirty-three million, four hundred eighty-one", and thus it is an aban number.
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