Base | Representation |
---|---|
bin | 111010100011111100110… |
… | …100110110000010011001 |
3 | 112020201111112221122212121 |
4 | 322203330310312002121 |
5 | 1011413312230202223 |
6 | 12320430245541241 |
7 | 563514450643456 |
oct | 72437464660231 |
9 | 15221445848777 |
10 | 4024331100313 |
11 | 1311788aa0437 |
12 | 54bb38414821 |
13 | 232653891604 |
14 | dcac892682d |
15 | 6ea370a015d |
hex | 3a8fcd36099 |
4024331100313 has 2 divisors, whose sum is σ = 4024331100314. Its totient is φ = 4024331100312.
The previous prime is 4024331100299. The next prime is 4024331100353. The reversal of 4024331100313 is 3130011334204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3203054725264 + 821276375049 = 1789708^2 + 906243^2 .
It is a cyclic number.
It is not a de Polignac number, because 4024331100313 - 29 = 4024331099801 is a prime.
It is not a weakly prime, because it can be changed into another prime (4024331100353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012165550156 + 2012165550157.
It is an arithmetic number, because the mean of its divisors is an integer number (2012165550157).
Almost surely, 24024331100313 is an apocalyptic number.
It is an amenable number.
4024331100313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024331100313 is an equidigital number, since it uses as much as digits as its factorization.
4024331100313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4024331100313 its reverse (3130011334204), we get a palindrome (7154342434517).
The spelling of 4024331100313 in words is "four trillion, twenty-four billion, three hundred thirty-one million, one hundred thousand, three hundred thirteen".
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