Base | Representation |
---|---|
bin | 111010100100110011111… |
… | …001101011100101101001 |
3 | 112020210212221122110212222 |
4 | 322210303321223211221 |
5 | 1011422210302140423 |
6 | 12321102054443425 |
7 | 563546400642251 |
oct | 72446371534551 |
9 | 15223787573788 |
10 | 4025255115113 |
11 | 1312112635431 |
12 | 550155963575 |
13 | 23277014592b |
14 | dcb75534961 |
15 | 6ea8d2723c8 |
hex | 3a933e6b969 |
4025255115113 has 2 divisors, whose sum is σ = 4025255115114. Its totient is φ = 4025255115112.
The previous prime is 4025255115097. The next prime is 4025255115151. The reversal of 4025255115113 is 3115115525204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3426841475929 + 598413639184 = 1851173^2 + 773572^2 .
It is a cyclic number.
It is not a de Polignac number, because 4025255115113 - 24 = 4025255115097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (4025255117113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012627557556 + 2012627557557.
It is an arithmetic number, because the mean of its divisors is an integer number (2012627557557).
Almost surely, 24025255115113 is an apocalyptic number.
It is an amenable number.
4025255115113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4025255115113 is an equidigital number, since it uses as much as digits as its factorization.
4025255115113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 35.
The spelling of 4025255115113 in words is "four trillion, twenty-five billion, two hundred fifty-five million, one hundred fifteen thousand, one hundred thirteen".
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