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40253141315041 is a prime number
BaseRepresentation
bin10010010011100001010100…
…01100000110110111100001
312021112011101121222012120021
421021300222030012313201
520234001413134040131
6221340012101113441
711323123236524254
oct1111605214066741
9167464347865507
1040253141315041
111190a296969856
1246213b36b8881
13195cb163b8945
149d239619b09b
1549c1236e0e11
hex249c2a306de1

40253141315041 has 2 divisors, whose sum is σ = 40253141315042. Its totient is φ = 40253141315040.

The previous prime is 40253141314979. The next prime is 40253141315059. The reversal of 40253141315041 is 14051314135204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31755309984225 + 8497831330816 = 5635185^2 + 2915104^2 .

It is a cyclic number.

It is not a de Polignac number, because 40253141315041 - 227 = 40253007097313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40253141314988 and 40253141315006.

It is not a weakly prime, because it can be changed into another prime (40253141315641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20126570657520 + 20126570657521.

It is an arithmetic number, because the mean of its divisors is an integer number (20126570657521).

Almost surely, 240253141315041 is an apocalyptic number.

It is an amenable number.

40253141315041 is a deficient number, since it is larger than the sum of its proper divisors (1).

40253141315041 is an equidigital number, since it uses as much as digits as its factorization.

40253141315041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 40253141315041 in words is "forty trillion, two hundred fifty-three billion, one hundred forty-one million, three hundred fifteen thousand, forty-one".