Base | Representation |
---|---|
bin | 10010010100111000110011… |
… | …11001000101101100000001 |
3 | 12021200122122010121101001122 |
4 | 21022130121321011230001 |
5 | 20240234112302044043 |
6 | 221413341025242025 |
7 | 11326405233354344 |
oct | 1112343171055401 |
9 | 167618563541048 |
10 | 40300112534273 |
11 | 119281aa9a3aa9 |
12 | 462a522193315 |
13 | 19643908080a7 |
14 | 9d477055245b |
15 | 49d472209368 |
hex | 24a719e45b01 |
40300112534273 has 2 divisors, whose sum is σ = 40300112534274. Its totient is φ = 40300112534272.
The previous prime is 40300112534263. The next prime is 40300112534299. The reversal of 40300112534273 is 37243521100304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30013929379009 + 10286183155264 = 5478497^2 + 3207208^2 .
It is a cyclic number.
It is not a de Polignac number, because 40300112534273 - 212 = 40300112530177 is a prime.
It is not a weakly prime, because it can be changed into another prime (40300112534263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20150056267136 + 20150056267137.
It is an arithmetic number, because the mean of its divisors is an integer number (20150056267137).
Almost surely, 240300112534273 is an apocalyptic number.
It is an amenable number.
40300112534273 is a deficient number, since it is larger than the sum of its proper divisors (1).
40300112534273 is an equidigital number, since it uses as much as digits as its factorization.
40300112534273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 40300112534273 its reverse (37243521100304), we get a palindrome (77543633634577).
The spelling of 40300112534273 in words is "forty trillion, three hundred billion, one hundred twelve million, five hundred thirty-four thousand, two hundred seventy-three".
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