4031022000121 has 2 divisors, whose sum is σ = 4031022000122. Its totient is φ = 4031022000120.

The previous prime is 4031022000107. The next prime is 4031022000127. The reversal of 4031022000121 is 1210002201304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2961276538896 + 1069745461225 = 1720836^2 + 1034285^2 .

It is a cyclic number.

It is not a de Polignac number, because 4031022000121 - 2⁷ = 4031021999993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4031022000095 and 4031022000104.

It is not a weakly prime, because it can be changed into another prime (4031022000127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015511000060 + 2015511000061.

It is an arithmetic number, because the mean of its divisors is an integer number (2015511000061).

Almost surely, 2^{4031022000121} is an apocalyptic number.

It is an amenable number.

4031022000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4031022000121 is an equidigital number, since it uses as much as digits as its factorization.

4031022000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 4031022000121 its reverse (1210002201304), we get a palindrome (5241024201425).

The spelling of 4031022000121 in words is "four trillion, thirty-one billion, twenty-two million, one hundred twenty-one", and thus it is an aban number.