Base | Representation |
---|---|
bin | 10010010101010001101000… |
… | …10010001011111101001011 |
3 | 12021201221000222000010000112 |
4 | 21022220310102023331023 |
5 | 20240443411144114201 |
6 | 221423423324024535 |
7 | 11330356426013012 |
oct | 1112506422137513 |
9 | 167657028003015 |
10 | 40313440223051 |
11 | 1193291a044926 |
12 | 463102169214b |
13 | 1965705a50878 |
14 | 9d527661ba79 |
15 | 49d9a22d90bb |
hex | 24aa3448bf4b |
40313440223051 has 2 divisors, whose sum is σ = 40313440223052. Its totient is φ = 40313440223050.
The previous prime is 40313440223039. The next prime is 40313440223141. The reversal of 40313440223051 is 15032204431304.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40313440223051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40313440222999 and 40313440223017.
It is not a weakly prime, because it can be changed into another prime (40313440423051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20156720111525 + 20156720111526.
It is an arithmetic number, because the mean of its divisors is an integer number (20156720111526).
Almost surely, 240313440223051 is an apocalyptic number.
40313440223051 is a deficient number, since it is larger than the sum of its proper divisors (1).
40313440223051 is an equidigital number, since it uses as much as digits as its factorization.
40313440223051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 40313440223051 its reverse (15032204431304), we get a palindrome (55345644654355).
The spelling of 40313440223051 in words is "forty trillion, three hundred thirteen billion, four hundred forty million, two hundred twenty-three thousand, fifty-one".
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