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40314151421153 = 128983312553991
BaseRepresentation
bin10010010101010010111101…
…01011001100010011100001
312021201222212112020201101222
421022221132223030103201
520241001340230434103
6221424022051304425
711330413153053611
oct1112513653142341
9167658775221358
1040314151421153
1111933154542555
12463119b8ab115
1319657ba1b0c4c
149d5302c6ca41
1549d9e496e638
hex24aa5eacc4e1

40314151421153 has 4 divisors (see below), whose sum is σ = 40314464104128. Its totient is φ = 40313838738180.

The previous prime is 40314151421143. The next prime is 40314151421209. The reversal of 40314151421153 is 35112415141304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40314151421153 - 226 = 40314084312289 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40314151421113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156148013 + ... + 156405978.

It is an arithmetic number, because the mean of its divisors is an integer number (10078616026032).

Almost surely, 240314151421153 is an apocalyptic number.

It is an amenable number.

40314151421153 is a deficient number, since it is larger than the sum of its proper divisors (312682975).

40314151421153 is a wasteful number, since it uses less digits than its factorization.

40314151421153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312682974.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 40314151421153 its reverse (35112415141304), we get a palindrome (75426566562457).

The spelling of 40314151421153 in words is "forty trillion, three hundred fourteen billion, one hundred fifty-one million, four hundred twenty-one thousand, one hundred fifty-three".

Divisors: 1 128983 312553991 40314151421153