Base | Representation |
---|---|
bin | 101101110101111000110101… |
… | …0110111111001010010011011 |
3 | 1221212201110102000221111200011 |
4 | 1123223301222313321102123 |
5 | 410323012032134431011 |
6 | 3545333311410222351 |
7 | 150635304520265224 |
oct | 13353615267712233 |
9 | 1855643360844604 |
10 | 403230502655131 |
11 | 107533106607868 |
12 | 392849335849b7 |
13 | 143cc61c936688 |
14 | 718066371424b |
15 | 3193e3db10621 |
hex | 16ebc6adf949b |
403230502655131 has 2 divisors, whose sum is σ = 403230502655132. Its totient is φ = 403230502655130.
The previous prime is 403230502655083. The next prime is 403230502655147. The reversal of 403230502655131 is 131556205032304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 403230502655131 - 27 = 403230502655003 is a prime.
It is a super-2 number, since 2×4032305026551312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (403230502635131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201615251327565 + 201615251327566.
It is an arithmetic number, because the mean of its divisors is an integer number (201615251327566).
Almost surely, 2403230502655131 is an apocalyptic number.
403230502655131 is a deficient number, since it is larger than the sum of its proper divisors (1).
403230502655131 is an equidigital number, since it uses as much as digits as its factorization.
403230502655131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 40.
Adding to 403230502655131 its reverse (131556205032304), we get a palindrome (534786707687435).
The spelling of 403230502655131 in words is "four hundred three trillion, two hundred thirty billion, five hundred two million, six hundred fifty-five thousand, one hundred thirty-one".
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