Base | Representation |
---|---|
bin | 10010010101100011110101… |
… | …00111110010001000000011 |
3 | 12021202212020211222120221101 |
4 | 21022301322213302020003 |
5 | 20241123413304133011 |
6 | 221432121013035231 |
7 | 11331153511445122 |
oct | 1112617247621003 |
9 | 167685224876841 |
10 | 40323210224131 |
11 | 11936a82a4728a |
12 | 4632aa9625b17 |
13 | 1966601bac3b3 |
14 | 9d5921dcdab9 |
15 | 49dd74db42c1 |
hex | 24ac7a9f2203 |
40323210224131 has 2 divisors, whose sum is σ = 40323210224132. Its totient is φ = 40323210224130.
The previous prime is 40323210224093. The next prime is 40323210224287. The reversal of 40323210224131 is 13142201232304.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40323210224131 - 229 = 40322673353219 is a prime.
It is a super-2 number, since 2×403232102241312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40323210224131.
It is not a weakly prime, because it can be changed into another prime (40323210294131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20161605112065 + 20161605112066.
It is an arithmetic number, because the mean of its divisors is an integer number (20161605112066).
Almost surely, 240323210224131 is an apocalyptic number.
40323210224131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40323210224131 is an equidigital number, since it uses as much as digits as its factorization.
40323210224131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 40323210224131 its reverse (13142201232304), we get a palindrome (53465411456435).
The spelling of 40323210224131 in words is "forty trillion, three hundred twenty-three billion, two hundred ten million, two hundred twenty-four thousand, one hundred thirty-one".
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