Base | Representation |
---|---|
bin | 111010101100011001011… |
… | …101011000010011000011 |
3 | 112021120220200100210112111 |
4 | 322230121131120103003 |
5 | 1012040401231014133 |
6 | 12324530302240151 |
7 | 564255306264166 |
oct | 72543135302303 |
9 | 15246820323474 |
10 | 4033401423043 |
11 | 1315612a53123 |
12 | 551849b86057 |
13 | 23346aa94295 |
14 | dd309405add |
15 | 6edb851d1cd |
hex | 3ab197584c3 |
4033401423043 has 2 divisors, whose sum is σ = 4033401423044. Its totient is φ = 4033401423042.
The previous prime is 4033401422987. The next prime is 4033401423047. The reversal of 4033401423043 is 3403241043304.
4033401423043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4033401423043 - 213 = 4033401414851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4033401422996 and 4033401423014.
It is not a weakly prime, because it can be changed into another prime (4033401423047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016700711521 + 2016700711522.
It is an arithmetic number, because the mean of its divisors is an integer number (2016700711522).
Almost surely, 24033401423043 is an apocalyptic number.
4033401423043 is a deficient number, since it is larger than the sum of its proper divisors (1).
4033401423043 is an equidigital number, since it uses as much as digits as its factorization.
4033401423043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 4033401423043 its reverse (3403241043304), we get a palindrome (7436642466347).
The spelling of 4033401423043 in words is "four trillion, thirty-three billion, four hundred one million, four hundred twenty-three thousand, forty-three".
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