Base | Representation |
---|---|
bin | 10010010110000111110000… |
… | …11010011100000100110111 |
3 | 12021211201001020002101002210 |
4 | 21023003320122130010313 |
5 | 20241432420113234333 |
6 | 221445031111104503 |
7 | 11332435525341333 |
oct | 1113037032340467 |
9 | 167751036071083 |
10 | 40342500524343 |
11 | 11944181901356 |
12 | 4636791972133 |
13 | 196838752c914 |
14 | 9d6831d347c3 |
15 | 49e603693a63 |
hex | 24b0f869c137 |
40342500524343 has 16 divisors (see below), whose sum is σ = 55222525211616. Its totient is φ = 26181608885760.
The previous prime is 40342500524311. The next prime is 40342500524369. The reversal of 40342500524343 is 34342500524304.
It is not a de Polignac number, because 40342500524343 - 25 = 40342500524311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40342500524303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 358792596 + ... + 358905017.
It is an arithmetic number, because the mean of its divisors is an integer number (3451407825726).
Almost surely, 240342500524343 is an apocalyptic number.
40342500524343 is a deficient number, since it is larger than the sum of its proper divisors (14880024687273).
40342500524343 is a wasteful number, since it uses less digits than its factorization.
40342500524343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 717698114.
The product of its (nonzero) digits is 691200, while the sum is 39.
Subtracting from 40342500524343 its sum of digits (39), we obtain a palindrome (40342500524304).
The spelling of 40342500524343 in words is "forty trillion, three hundred forty-two billion, five hundred million, five hundred twenty-four thousand, three hundred forty-three".
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