Base | Representation |
---|---|
bin | 1011101111011101000… |
… | …10100100111110111001 |
3 | 1102120100000020122211121 |
4 | 11313232202210332321 |
5 | 23102213101002223 |
6 | 505200210425241 |
7 | 41101320264511 |
oct | 5675642447671 |
9 | 1376300218747 |
10 | 403434000313 |
11 | 146105a80693 |
12 | 66231292221 |
13 | 2c074c09ba6 |
14 | 157522a0841 |
15 | a76311a15d |
hex | 5dee8a4fb9 |
403434000313 has 2 divisors, whose sum is σ = 403434000314. Its totient is φ = 403434000312.
The previous prime is 403434000289. The next prime is 403434000331. The reversal of 403434000313 is 313000434304.
Together with next prime (403434000331) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 348515483904 + 54918516409 = 590352^2 + 234347^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-403434000313 is a prime.
It is not a weakly prime, because it can be changed into another prime (403434000383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201717000156 + 201717000157.
It is an arithmetic number, because the mean of its divisors is an integer number (201717000157).
Almost surely, 2403434000313 is an apocalyptic number.
It is an amenable number.
403434000313 is a deficient number, since it is larger than the sum of its proper divisors (1).
403434000313 is an equidigital number, since it uses as much as digits as its factorization.
403434000313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 403434000313 its reverse (313000434304), we get a palindrome (716434434617).
The spelling of 403434000313 in words is "four hundred three billion, four hundred thirty-four million, three hundred thirteen", and thus it is an aban number.
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