Base | Representation |
---|---|
bin | 10010010110011001011110… |
… | …10010111010111100111011 |
3 | 12021212121121001011112121111 |
4 | 21023030233102322330323 |
5 | 20242111404334011011 |
6 | 221453242534421151 |
7 | 11333223312136201 |
oct | 1113145722727473 |
9 | 167777531145544 |
10 | 40352011235131 |
11 | 11948212405112 |
12 | 46385a6b017b7 |
13 | 1969241a4523b |
14 | 9d70950cd071 |
15 | 49e9ad602121 |
hex | 24b32f4baf3b |
40352011235131 has 2 divisors, whose sum is σ = 40352011235132. Its totient is φ = 40352011235130.
The previous prime is 40352011235071. The next prime is 40352011235141. The reversal of 40352011235131 is 13153211025304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40352011235131 - 237 = 40214572281659 is a prime.
It is a super-2 number, since 2×403520112351312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40352011235093 and 40352011235102.
It is not a weakly prime, because it can be changed into another prime (40352011235141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20176005617565 + 20176005617566.
It is an arithmetic number, because the mean of its divisors is an integer number (20176005617566).
Almost surely, 240352011235131 is an apocalyptic number.
40352011235131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40352011235131 is an equidigital number, since it uses as much as digits as its factorization.
40352011235131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 40352011235131 in words is "forty trillion, three hundred fifty-two billion, eleven million, two hundred thirty-five thousand, one hundred thirty-one".
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