Base | Representation |
---|---|
bin | 111010110010011101001… |
… | …011001111100101011011 |
3 | 112022012201000022011012202 |
4 | 322302131023033211123 |
5 | 1012142211443303241 |
6 | 12331523551000415 |
7 | 564605433232613 |
oct | 72623513174533 |
9 | 15265630264182 |
10 | 4039906228571 |
11 | 1318350822864 |
12 | 552b6450910b |
13 | 233c66608535 |
14 | dd76529ba43 |
15 | 7014961cd9b |
hex | 3ac9d2cf95b |
4039906228571 has 4 divisors (see below), whose sum is σ = 4252532872200. Its totient is φ = 3827279584944.
The previous prime is 4039906228543. The next prime is 4039906228669. The reversal of 4039906228571 is 1758226099304.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4039906228571 - 26 = 4039906228507 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4039906228531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106313321786 + ... + 106313321823.
It is an arithmetic number, because the mean of its divisors is an integer number (1063133218050).
It is a 1-persistent number, because it is pandigital, but 2⋅4039906228571 = 8079812457142 is not.
Almost surely, 24039906228571 is an apocalyptic number.
4039906228571 is a deficient number, since it is larger than the sum of its proper divisors (212626643629).
4039906228571 is a wasteful number, since it uses less digits than its factorization.
4039906228571 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 212626643628.
The product of its (nonzero) digits is 6531840, while the sum is 56.
The spelling of 4039906228571 in words is "four trillion, thirty-nine billion, nine hundred six million, two hundred twenty-eight thousand, five hundred seventy-one".
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