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4040040233121 = 31346680077707
BaseRepresentation
bin111010110010100101001…
…010011011100010100001
3112022020001100110021220020
4322302211022123202201
51012143000244424441
612331545135104053
7564611651242464
oct72624512334241
915266040407806
104040040233121
11131840a42a422
12552ba1372029
13233c882c6979
14dd778dc12db
157015628ce66
hex3aca529b8a1

4040040233121 has 4 divisors (see below), whose sum is σ = 5386720310832. Its totient is φ = 2693360155412.

The previous prime is 4040040233113. The next prime is 4040040233147. The reversal of 4040040233121 is 1213320400404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4040040233121 - 23 = 4040040233113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4040040233091 and 4040040233100.

It is not an unprimeable number, because it can be changed into a prime (4040040253121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673340038851 + ... + 673340038856.

It is an arithmetic number, because the mean of its divisors is an integer number (1346680077708).

Almost surely, 24040040233121 is an apocalyptic number.

It is an amenable number.

4040040233121 is a deficient number, since it is larger than the sum of its proper divisors (1346680077711).

4040040233121 is a wasteful number, since it uses less digits than its factorization.

4040040233121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1346680077710.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 4040040233121 its reverse (1213320400404), we get a palindrome (5253360633525).

The spelling of 4040040233121 in words is "four trillion, forty billion, forty million, two hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 3 1346680077707 4040040233121