Base | Representation |
---|---|
bin | 111010110010100101001… |
… | …010011011100010100001 |
3 | 112022020001100110021220020 |
4 | 322302211022123202201 |
5 | 1012143000244424441 |
6 | 12331545135104053 |
7 | 564611651242464 |
oct | 72624512334241 |
9 | 15266040407806 |
10 | 4040040233121 |
11 | 131840a42a422 |
12 | 552ba1372029 |
13 | 233c882c6979 |
14 | dd778dc12db |
15 | 7015628ce66 |
hex | 3aca529b8a1 |
4040040233121 has 4 divisors (see below), whose sum is σ = 5386720310832. Its totient is φ = 2693360155412.
The previous prime is 4040040233113. The next prime is 4040040233147. The reversal of 4040040233121 is 1213320400404.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4040040233121 - 23 = 4040040233113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4040040233091 and 4040040233100.
It is not an unprimeable number, because it can be changed into a prime (4040040253121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673340038851 + ... + 673340038856.
It is an arithmetic number, because the mean of its divisors is an integer number (1346680077708).
Almost surely, 24040040233121 is an apocalyptic number.
It is an amenable number.
4040040233121 is a deficient number, since it is larger than the sum of its proper divisors (1346680077711).
4040040233121 is a wasteful number, since it uses less digits than its factorization.
4040040233121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1346680077710.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 4040040233121 its reverse (1213320400404), we get a palindrome (5253360633525).
The spelling of 4040040233121 in words is "four trillion, forty billion, forty million, two hundred thirty-three thousand, one hundred twenty-one".
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