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40401131473 is a prime number
BaseRepresentation
bin100101101000000110…
…000101011111010001
310212021121212010102201
4211220012011133101
51130220142201343
630320544243201
72630114644213
oct455006053721
9125247763381
1040401131473
111615242705a
1279b6310501
133a6b1cbb71
141d539885b3
1510b6d2094d
hex9681857d1

40401131473 has 2 divisors, whose sum is σ = 40401131474. Its totient is φ = 40401131472.

The previous prime is 40401131467. The next prime is 40401131497. The reversal of 40401131473 is 37413110404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21086524944 + 19314606529 = 145212^2 + 138977^2 .

It is a cyclic number.

It is not a de Polignac number, because 40401131473 - 213 = 40401123281 is a prime.

It is a super-2 number, since 2×404011314732 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40401131453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20200565736 + 20200565737.

It is an arithmetic number, because the mean of its divisors is an integer number (20200565737).

Almost surely, 240401131473 is an apocalyptic number.

It is an amenable number.

40401131473 is a deficient number, since it is larger than the sum of its proper divisors (1).

40401131473 is an equidigital number, since it uses as much as digits as its factorization.

40401131473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 40401131473 its reverse (37413110404), we get a palindrome (77814241877).

The spelling of 40401131473 in words is "forty billion, four hundred one million, one hundred thirty-one thousand, four hundred seventy-three".