Search a number
-
+
40401538754129 = 75771648393447
BaseRepresentation
bin10010010111110101101110…
…10111011010011001010001
312022001100102200221012010222
421023322313113122121101
520243414322410113004
6221532113301202425
711336625536121260
oct1113726727323121
9168040380835128
1040401538754129
11119672183a71a3
124646109700415
131970b059467b7
149d9632b8c5d7
154a0e0b7677be
hex24beb75da651

40401538754129 has 4 divisors (see below), whose sum is σ = 46173187147584. Its totient is φ = 34629890360676.

The previous prime is 40401538754099. The next prime is 40401538754141. The reversal of 40401538754129 is 92145783510404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40401538754129 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (40401538754429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2885824196717 + ... + 2885824196730.

It is an arithmetic number, because the mean of its divisors is an integer number (11543296786896).

Almost surely, 240401538754129 is an apocalyptic number.

It is an amenable number.

40401538754129 is a deficient number, since it is larger than the sum of its proper divisors (5771648393455).

40401538754129 is an equidigital number, since it uses as much as digits as its factorization.

40401538754129 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5771648393454.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 40401538754129 in words is "forty trillion, four hundred one billion, five hundred thirty-eight million, seven hundred fifty-four thousand, one hundred twenty-nine".

Divisors: 1 7 5771648393447 40401538754129