404032313131 has 4 divisors (see below), whose sum is σ = 404035582032. Its totient is φ = 404029044232.

The previous prime is 404032313129. The next prime is 404032313147. The reversal of 404032313131 is 131313230404.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 404032313131 - 2¹ = 404032313129 is a prime.

It is a super-2 number, since 2×404032313131² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 404032313096 and 404032313105.

It is not an unprimeable number, because it can be changed into a prime (404032311131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1441456 + ... + 1698781.

It is an arithmetic number, because the mean of its divisors is an integer number (101008895508).

Almost surely, 2^404032313131 is an apocalyptic number.

404032313131 is a deficient number, since it is larger than the sum of its proper divisors (3268901).

404032313131 is a wasteful number, since it uses less digits than its factorization.

404032313131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3268900.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 404032313131 its reverse (131313230404), we get a palindrome (535345543535).

The spelling of 404032313131 in words is "four hundred four billion, thirty-two million, three hundred thirteen thousand, one hundred thirty-one".