4040352404131 has 4 divisors (see below), whose sum is σ = 4134314087992. Its totient is φ = 3946390720272.

The previous prime is 4040352404129. The next prime is 4040352404147. The reversal of 4040352404131 is 1314042530404.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4040352404131 - 2¹ = 4040352404129 is a prime.

It is a super-2 number, since 2×4040352404131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4040352404093 and 4040352404102.

It is not an unprimeable number, because it can be changed into a prime (4040352404161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46980841866 + ... + 46980841951.

It is an arithmetic number, because the mean of its divisors is an integer number (1033578521998).

Almost surely, 2^{4040352404131} is an apocalyptic number.

4040352404131 is a deficient number, since it is larger than the sum of its proper divisors (93961683861).

4040352404131 is an equidigital number, since it uses as much as digits as its factorization.

4040352404131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93961683860.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 4040352404131 its reverse (1314042530404), we get a palindrome (5354394934535).

The spelling of 4040352404131 in words is "four trillion, forty billion, three hundred fifty-two million, four hundred four thousand, one hundred thirty-one".