4042121201233 has 2 divisors, whose sum is σ = 4042121201234. Its totient is φ = 4042121201232.

The previous prime is 4042121201197. The next prime is 4042121201249. The reversal of 4042121201233 is 3321021212404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2267502907329 + 1774618293904 = 1505823^2 + 1332148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4042121201233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4042121201198 and 4042121201207.

It is not a weakly prime, because it can be changed into another prime (4042121201263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021060600616 + 2021060600617.

It is an arithmetic number, because the mean of its divisors is an integer number (2021060600617).

Almost surely, 2^{4042121201233} is an apocalyptic number.

It is an amenable number.

4042121201233 is a deficient number, since it is larger than the sum of its proper divisors (1).

4042121201233 is an equidigital number, since it uses as much as digits as its factorization.

4042121201233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4042121201233 its reverse (3321021212404), we get a palindrome (7363142413637).

The spelling of 4042121201233 in words is "four trillion, forty-two billion, one hundred twenty-one million, two hundred one thousand, two hundred thirty-three".