Base | Representation |
---|---|
bin | 111010110100101110011… |
… | …011111111001011100011 |
3 | 112022102222212002221010111 |
4 | 322310232123333023203 |
5 | 1012212204342023042 |
6 | 12333005450112151 |
7 | 565023015145435 |
oct | 72645633771343 |
9 | 15272885087114 |
10 | 4042343314147 |
11 | 1319391465276 |
12 | 55352471b657 |
13 | 2342644aa2c8 |
14 | dd916c12655 |
15 | 7023d56c517 |
hex | 3ad2e6ff2e3 |
4042343314147 has 2 divisors, whose sum is σ = 4042343314148. Its totient is φ = 4042343314146.
The previous prime is 4042343314063. The next prime is 4042343314153. The reversal of 4042343314147 is 7414133432404.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4042343314147 is a prime.
It is a super-3 number, since 3×40423433141473 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4042343714147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021171657073 + 2021171657074.
It is an arithmetic number, because the mean of its divisors is an integer number (2021171657074).
Almost surely, 24042343314147 is an apocalyptic number.
4042343314147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042343314147 is an equidigital number, since it uses as much as digits as its factorization.
4042343314147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 40.
The spelling of 4042343314147 in words is "four trillion, forty-two billion, three hundred forty-three million, three hundred fourteen thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •