Base | Representation |
---|---|
bin | 111010110101010110010… |
… | …111001011101100100011 |
3 | 112022111201112111210000210 |
4 | 322311112113023230203 |
5 | 1012220042331041311 |
6 | 12333200134545203 |
7 | 565045430460261 |
oct | 72652627135443 |
9 | 15274645453023 |
10 | 4043013143331 |
11 | 13196a5577908 |
12 | 553690b08203 |
13 | 2343401b4a36 |
14 | dd97bb75431 |
15 | 7027c2803a6 |
hex | 3ad565cbb23 |
4043013143331 has 16 divisors (see below), whose sum is σ = 5395448115200. Its totient is φ = 2692961106048.
The previous prime is 4043013143173. The next prime is 4043013143359. The reversal of 4043013143331 is 1333413103404.
It is not a de Polignac number, because 4043013143331 - 219 = 4043012619043 is a prime.
It is a super-2 number, since 2×40430131433312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4043013153331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16857030 + ... + 17095188.
It is an arithmetic number, because the mean of its divisors is an integer number (337215507200).
Almost surely, 24043013143331 is an apocalyptic number.
4043013143331 is a deficient number, since it is larger than the sum of its proper divisors (1352434971869).
4043013143331 is a wasteful number, since it uses less digits than its factorization.
4043013143331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243138.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 4043013143331 its reverse (1333413103404), we get a palindrome (5376426246735).
The spelling of 4043013143331 in words is "four trillion, forty-three billion, thirteen million, one hundred forty-three thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.175 sec. • engine limits •