4043302121 has 2 divisors, whose sum is σ = 4043302122. Its totient is φ = 4043302120.

The previous prime is 4043302093. The next prime is 4043302139. The reversal of 4043302121 is 1212033404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3342111721 + 701190400 = 57811^2 + 26480^2 .

It is a cyclic number.

It is not a de Polignac number, because 4043302121 - 2⁶ = 4043302057 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4043302093 and 4043302102.

It is not a weakly prime, because it can be changed into another prime (4043302621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021651060 + 2021651061.

It is an arithmetic number, because the mean of its divisors is an integer number (2021651061).

Almost surely, 2^4043302121 is an apocalyptic number.

It is an amenable number.

4043302121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4043302121 is an equidigital number, since it uses as much as digits as its factorization.

4043302121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 4043302121 is about 63586.9650242878. The cubic root of 4043302121 is about 1593.1086579974.

Adding to 4043302121 its reverse (1212033404), we get a palindrome (5255335525).

The spelling of 4043302121 in words is "four billion, forty-three million, three hundred two thousand, one hundred twenty-one".