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4043431113441 = 31347810371147
BaseRepresentation
bin111010110101101111010…
…001100111001011100001
3112022112210122222212020020
4322311233101213023201
51012221421331112231
612333305425304053
7565061664245106
oct72655721471341
915275718885206
104043431113441
11131989a4a6a55
12553788a95029
132343a8978825
14dd9bb496aad
15702a3ce3396
hex3ad6f4672e1

4043431113441 has 4 divisors (see below), whose sum is σ = 5391241484592. Its totient is φ = 2695620742292.

The previous prime is 4043431113433. The next prime is 4043431113467. The reversal of 4043431113441 is 1443111343404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4043431113441 - 23 = 4043431113433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4043431113431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 673905185571 + ... + 673905185576.

It is an arithmetic number, because the mean of its divisors is an integer number (1347810371148).

Almost surely, 24043431113441 is an apocalyptic number.

It is an amenable number.

4043431113441 is a deficient number, since it is larger than the sum of its proper divisors (1347810371151).

4043431113441 is a wasteful number, since it uses less digits than its factorization.

4043431113441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1347810371150.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 4043431113441 its reverse (1443111343404), we get a palindrome (5486542456845).

The spelling of 4043431113441 in words is "four trillion, forty-three billion, four hundred thirty-one million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 3 1347810371147 4043431113441