Base | Representation |
---|---|
bin | 10010011000110100010011… |
… | …01000011110011000101001 |
3 | 12022011120010211001221010102 |
4 | 21030122021220132120221 |
5 | 20244442122042311403 |
6 | 221555350504155145 |
7 | 11342225150244212 |
oct | 1114321150363051 |
9 | 168146124057112 |
10 | 40435131213353 |
11 | 1197a496478a98 |
12 | 4650723768ab5 |
13 | 197402a37b5c6 |
14 | 9db0dc382409 |
15 | 4a1c25963b88 |
hex | 24c689a1e629 |
40435131213353 has 2 divisors, whose sum is σ = 40435131213354. Its totient is φ = 40435131213352.
The previous prime is 40435131213289. The next prime is 40435131213427. The reversal of 40435131213353 is 35331213153404.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30509184814144 + 9925946399209 = 5523512^2 + 3150547^2 .
It is a cyclic number.
It is not a de Polignac number, because 40435131213353 - 26 = 40435131213289 is a prime.
It is not a weakly prime, because it can be changed into another prime (40435131212353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20217565606676 + 20217565606677.
It is an arithmetic number, because the mean of its divisors is an integer number (20217565606677).
Almost surely, 240435131213353 is an apocalyptic number.
It is an amenable number.
40435131213353 is a deficient number, since it is larger than the sum of its proper divisors (1).
40435131213353 is an equidigital number, since it uses as much as digits as its factorization.
40435131213353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
Adding to 40435131213353 its reverse (35331213153404), we get a palindrome (75766344366757).
The spelling of 40435131213353 in words is "forty trillion, four hundred thirty-five billion, one hundred thirty-one million, two hundred thirteen thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •