Base | Representation |
---|---|
bin | 111010110111100111101… |
… | …100100000110101111011 |
3 | 112022202000110120122022021 |
4 | 322313213230200311323 |
5 | 1012240041031300131 |
6 | 12334242115535311 |
7 | 565163025541444 |
oct | 72674754406573 |
9 | 15282013518267 |
10 | 4045451431291 |
11 | 131a736960726 |
12 | 5540515ba537 |
13 | 23463b3b7b8a |
14 | ddb2d9202cb |
15 | 7037136ae11 |
hex | 3ade7b20d7b |
4045451431291 has 2 divisors, whose sum is σ = 4045451431292. Its totient is φ = 4045451431290.
The previous prime is 4045451431279. The next prime is 4045451431309. The reversal of 4045451431291 is 1921341545404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4045451431291 - 213 = 4045451423099 is a prime.
It is a super-3 number, since 3×40454514312913 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4045451431261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2022725715645 + 2022725715646.
It is an arithmetic number, because the mean of its divisors is an integer number (2022725715646).
Almost surely, 24045451431291 is an apocalyptic number.
4045451431291 is a deficient number, since it is larger than the sum of its proper divisors (1).
4045451431291 is an equidigital number, since it uses as much as digits as its factorization.
4045451431291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 43.
Adding to 4045451431291 its reverse (1921341545404), we get a palindrome (5966792976695).
The spelling of 4045451431291 in words is "four trillion, forty-five billion, four hundred fifty-one million, four hundred thirty-one thousand, two hundred ninety-one".
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