Base | Representation |
---|---|
bin | 10010011010001101000110… |
… | …00011010110001101100001 |
3 | 12022100010012002200111012122 |
4 | 21031012203003112031201 |
5 | 20301232234344002132 |
6 | 222033313113434025 |
7 | 11345533403113031 |
oct | 1115064303261541 |
9 | 168303162614178 |
10 | 40482802328417 |
11 | 11998729591349 |
12 | 4659a0870b915 |
13 | 19786867a18b7 |
14 | 9dd5416858c1 |
15 | 4a30b5b2d912 |
hex | 24d1a30d6361 |
40482802328417 has 2 divisors, whose sum is σ = 40482802328418. Its totient is φ = 40482802328416.
The previous prime is 40482802328411. The next prime is 40482802328453. The reversal of 40482802328417 is 71482320828404.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25286807902801 + 15195994425616 = 5028599^2 + 3898204^2 .
It is a cyclic number.
It is not a de Polignac number, because 40482802328417 - 24 = 40482802328401 is a prime.
It is not a weakly prime, because it can be changed into another prime (40482802328411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20241401164208 + 20241401164209.
It is an arithmetic number, because the mean of its divisors is an integer number (20241401164209).
Almost surely, 240482802328417 is an apocalyptic number.
It is an amenable number.
40482802328417 is a deficient number, since it is larger than the sum of its proper divisors (1).
40482802328417 is an equidigital number, since it uses as much as digits as its factorization.
40482802328417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5505024, while the sum is 53.
The spelling of 40482802328417 in words is "forty trillion, four hundred eighty-two billion, eight hundred two million, three hundred twenty-eight thousand, four hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •