Base | Representation |
---|---|
bin | 111010111010010010101… |
… | …011001110111111010001 |
3 | 112100000102101022000202001 |
4 | 322322102223032333101 |
5 | 1012311424404444303 |
6 | 12335434511154001 |
7 | 565324100142415 |
oct | 72722253167721 |
9 | 15300371260661 |
10 | 4048319999953 |
11 | 1320979111829 |
12 | 554712215901 |
13 | 2349a77a2298 |
14 | ddd228b2d45 |
15 | 7048d0ec31d |
hex | 3ae92acefd1 |
4048319999953 has 2 divisors, whose sum is σ = 4048319999954. Its totient is φ = 4048319999952.
The previous prime is 4048319999929. The next prime is 4048320000007. The reversal of 4048319999953 is 3599999138404.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3968450457409 + 79869542544 = 1992097^2 + 282612^2 .
It is a cyclic number.
It is not a de Polignac number, because 4048319999953 - 233 = 4039730065361 is a prime.
It is not a weakly prime, because it can be changed into another prime (4048319999903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2024159999976 + 2024159999977.
It is an arithmetic number, because the mean of its divisors is an integer number (2024159999977).
Almost surely, 24048319999953 is an apocalyptic number.
It is an amenable number.
4048319999953 is a deficient number, since it is larger than the sum of its proper divisors (1).
4048319999953 is an equidigital number, since it uses as much as digits as its factorization.
4048319999953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 340122240, while the sum is 73.
The spelling of 4048319999953 in words is "four trillion, forty-eight billion, three hundred nineteen million, nine hundred ninety-nine thousand, nine hundred fifty-three".
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