Base | Representation |
---|---|
bin | 1011110010100101011… |
… | …11101010111011000001 |
3 | 1102201200011122010022011 |
4 | 11321102233222323001 |
5 | 23114133434412423 |
6 | 510035103412521 |
7 | 41161062664525 |
oct | 5712257527301 |
9 | 1381604563264 |
10 | 405115154113 |
11 | 146898a4139a |
12 | 666202b4141 |
13 | 2c2822b8257 |
14 | 1587167bd85 |
15 | a8109e9b0d |
hex | 5e52beaec1 |
405115154113 has 4 divisors (see below), whose sum is σ = 405177784660. Its totient is φ = 405052523568.
The previous prime is 405115154069. The next prime is 405115154173. The reversal of 405115154113 is 311451511504.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 167650940304 + 237464213809 = 409452^2 + 487303^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-405115154113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (405115154173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31305570 + ... + 31318507.
It is an arithmetic number, because the mean of its divisors is an integer number (101294446165).
Almost surely, 2405115154113 is an apocalyptic number.
It is an amenable number.
405115154113 is a deficient number, since it is larger than the sum of its proper divisors (62630547).
405115154113 is an equidigital number, since it uses as much as digits as its factorization.
405115154113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62630546.
The product of its (nonzero) digits is 6000, while the sum is 31.
Adding to 405115154113 its reverse (311451511504), we get a palindrome (716566665617).
The spelling of 405115154113 in words is "four hundred five billion, one hundred fifteen million, one hundred fifty-four thousand, one hundred thirteen".
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