Base | Representation |
---|---|
bin | 10010011011000111110111… |
… | …10000110011100110000011 |
3 | 12022110010122002101011211011 |
4 | 21031203323300303212003 |
5 | 20302241344441130311 |
6 | 222100012105501351 |
7 | 11351031331644304 |
oct | 1115437360634603 |
9 | 168403562334734 |
10 | 40514355411331 |
11 | 11a0005047157a |
12 | 4663b537a1857 |
13 | 197b644853669 |
14 | a00c960907ab |
15 | 4a3d10c8a321 |
hex | 24d8fbc33983 |
40514355411331 has 2 divisors, whose sum is σ = 40514355411332. Its totient is φ = 40514355411330.
The previous prime is 40514355411317. The next prime is 40514355411451. The reversal of 40514355411331 is 13311455341504.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40514355411331 - 239 = 39964599597443 is a prime.
It is a super-2 number, since 2×405143554113312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40514355411931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20257177705665 + 20257177705666.
It is an arithmetic number, because the mean of its divisors is an integer number (20257177705666).
Almost surely, 240514355411331 is an apocalyptic number.
40514355411331 is a deficient number, since it is larger than the sum of its proper divisors (1).
40514355411331 is an equidigital number, since it uses as much as digits as its factorization.
40514355411331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 40.
The spelling of 40514355411331 in words is "forty trillion, five hundred fourteen billion, three hundred fifty-five million, four hundred eleven thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •