Base | Representation |
---|---|
bin | 111010111101101110110… |
… | …001001000000110111001 |
3 | 112100100221201110002122220 |
4 | 322331232301020012321 |
5 | 1012342010202012103 |
6 | 12341245135034253 |
7 | 565514435144415 |
oct | 72755661100671 |
9 | 15310851402586 |
10 | 4052012532153 |
11 | 13224a3490933 |
12 | 55538296b989 |
13 | 2351457aca91 |
14 | 10019306bd45 |
15 | 7060738ac53 |
hex | 3af6ec481b9 |
4052012532153 has 16 divisors (see below), whose sum is σ = 5517780602880. Its totient is φ = 2643796127376.
The previous prime is 4052012532151. The next prime is 4052012532163. The reversal of 4052012532153 is 3512352102504.
4052012532153 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4052012532153 - 21 = 4052012532151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4052012532151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5239818 + ... + 5963196.
It is an arithmetic number, because the mean of its divisors is an integer number (344861287680).
Almost surely, 24052012532153 is an apocalyptic number.
It is an amenable number.
4052012532153 is a deficient number, since it is larger than the sum of its proper divisors (1465768070727).
4052012532153 is a wasteful number, since it uses less digits than its factorization.
4052012532153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 763156.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 4052012532153 its reverse (3512352102504), we get a palindrome (7564364634657).
The spelling of 4052012532153 in words is "four trillion, fifty-two billion, twelve million, five hundred thirty-two thousand, one hundred fifty-three".
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