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40531214393 is a prime number
BaseRepresentation
bin100101101111110110…
…010100000000111001
310212121200122000122122
4211233312110000321
51131001442330033
630341512331025
72633254431545
oct455766240071
9125550560578
1040531214393
11162098a52aa
127a319a3a75
133a8c1462c7
141d66d6aa25
1510c3468a98
hex96fd94039

40531214393 has 2 divisors, whose sum is σ = 40531214394. Its totient is φ = 40531214392.

The previous prime is 40531214389. The next prime is 40531214419. The reversal of 40531214393 is 39341213504.

40531214393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22259744809 + 18271469584 = 149197^2 + 135172^2 .

It is a cyclic number.

It is not a de Polignac number, because 40531214393 - 22 = 40531214389 is a prime.

It is not a weakly prime, because it can be changed into another prime (40531214363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20265607196 + 20265607197.

It is an arithmetic number, because the mean of its divisors is an integer number (20265607197).

Almost surely, 240531214393 is an apocalyptic number.

It is an amenable number.

40531214393 is a deficient number, since it is larger than the sum of its proper divisors (1).

40531214393 is an equidigital number, since it uses as much as digits as its factorization.

40531214393 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 40531214393 its reverse (39341213504), we get a palindrome (79872427897).

The spelling of 40531214393 in words is "forty billion, five hundred thirty-one million, two hundred fourteen thousand, three hundred ninety-three".