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40533548486257 is a prime number
BaseRepresentation
bin10010011011101011100111…
…10000100100111001110001
312022111222011200112101222001
421031311303300210321301
520303100201403030012
6222112504412014001
711352311055253051
oct1115656360447161
9168458150471861
1040533548486257
1111a081aa45a872
12466780b461301
1319803b2cc2328
14a01b97127561
154a4585c62357
hex24dd73c24e71

40533548486257 has 2 divisors, whose sum is σ = 40533548486258. Its totient is φ = 40533548486256.

The previous prime is 40533548486209. The next prime is 40533548486267. The reversal of 40533548486257 is 75268484533504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38319764567616 + 2213783918641 = 6190296^2 + 1487879^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40533548486257 is a prime.

It is a super-2 number, since 2×405335484862572 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40533548486267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20266774243128 + 20266774243129.

It is an arithmetic number, because the mean of its divisors is an integer number (20266774243129).

Almost surely, 240533548486257 is an apocalyptic number.

It is an amenable number.

40533548486257 is a deficient number, since it is larger than the sum of its proper divisors (1).

40533548486257 is an equidigital number, since it uses as much as digits as its factorization.

40533548486257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 387072000, while the sum is 64.

The spelling of 40533548486257 in words is "forty trillion, five hundred thirty-three billion, five hundred forty-eight million, four hundred eighty-six thousand, two hundred fifty-seven".