Base | Representation |
---|---|
bin | 10010011100001100001100… |
… | …11011111101011101100001 |
3 | 12022120122022211010122210012 |
4 | 21032012012123331131201 |
5 | 20303342013134434423 |
6 | 222124520312414305 |
7 | 11353500421262033 |
oct | 1116060633753541 |
9 | 168518284118705 |
10 | 40551041718113 |
11 | 11a14666982883 |
12 | 466b0919a7395 |
13 | 1981c4023acb4 |
14 | a02976519c53 |
15 | 4a4c5b8b7078 |
hex | 24e1866fd761 |
40551041718113 has 4 divisors (see below), whose sum is σ = 40763350837248. Its totient is φ = 40338732598980.
The previous prime is 40551041718071. The next prime is 40551041718133. The reversal of 40551041718113 is 31181714015504.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 40551041718113 - 240 = 39451530090337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40551041718133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106154559281 + ... + 106154559662.
It is an arithmetic number, because the mean of its divisors is an integer number (10190837709312).
Almost surely, 240551041718113 is an apocalyptic number.
It is an amenable number.
40551041718113 is a deficient number, since it is larger than the sum of its proper divisors (212309119135).
40551041718113 is a wasteful number, since it uses less digits than its factorization.
40551041718113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212309119134.
The product of its (nonzero) digits is 67200, while the sum is 41.
The spelling of 40551041718113 in words is "forty trillion, five hundred fifty-one billion, forty-one million, seven hundred eighteen thousand, one hundred thirteen".
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